Recent Posts

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41
General Board / Re: How to create operations and receptions in a block using SysML?
« Last post by qwerty on February 18, 2018, 10:49:57 am »
You need to write a shape script to create such an appearance. You can add custom compartments. I'm not sure about the operations which usually have their pre-defined and un-named compartment.

q.
42
General Board / How to create operations and receptions in a block using SysML?
« Last post by jackholdon on February 18, 2018, 05:05:03 am »
I was wondering how can I create operations and receptions in a block in a block definition diagram so they look like in the SysML specification, example from the official SysML spec:

https://imgur.com/MpXYTie

My questions are:

1 - I am able to create operations by right clicking the block and in the operations menu, however is it possible to make the block display the operations compartment name?
2 - How do I create receptions? I've tried to add the signal stereotype to operations I have created with the same name as already existing signals but when trying to assign the signal stereotype to the operations in the operation creation window the signal stereotype doesn't seem to be included in the SysML 1.4 set of stereotypes.
3 - How can I make the block display the receptions compartment name?

Thank you for your time.
43
Thank you KP, that worked as intended.
44
General Board / Re: Modelling Data Hierarchy with SysML
« Last post by quarter on February 17, 2018, 12:57:04 am »
OK, thanks.  I'll try both. 
45
Automation Interface, Add-Ins and Tools / WebEA user authentication
« Last post by Uffe on February 17, 2018, 12:05:54 am »
Hi all,


I'm evaluating WebEA for a client. According to the WebEA Login help page, in addition to some "access code" I cannot see any point of, WebEA supports "standard Enterprise Architect model security." However, the page then states that login credentials can include
  • An access code, or
  • A user ID and password, or
  • Possibly all three
Ignoring the fact that "all three" makes no sense since you can't provide just a password with no user ID, what about Windows domain authentication? It's part of standard EA model security, but it's not in the list.

Can you authenticate WebEA users against a domain, or not?

What happens if you configure a project for windows authentication, and configure WebEA to prompt user ID and password?
Should users provide a blank password?
Is the password ignored?
Or will users be unable to log in?

What happens if you configure a project for windows authentication, and configure WebEA to prompt for an access code, or no authentication at all?
Are users correctly identified in the project (in Author fields etc)?


/Uffe
46
General Board / Re: Table tool in Win32 User Interface
« Last post by Arshad on February 16, 2018, 09:29:19 pm »
You can't edit the cells in table object of Extended UI Diagram.

If you need a editable table in User Interface , Please use the Table from Wireframing->Dialog->Table..
If its not available please check whether its enabled in MDG.

For more details refer
http://sparxsystems.com/enterprise_architect_user_guide/13.0/model_domains/dialog_wireframe_toolbox.html

HTH
Arshad
47
General Board / Table tool in Win32 User Interface
« Last post by Tafadzwa on February 16, 2018, 09:14:46 pm »
I'm new to EA and I'm trying to design a user interface using UML Extended  User Interface. The Table tool brings out a table but cant seem to input anything into like labels . Can someone please assist :'(
48
Hi there,

I try to generate a documentation on package_1 by using virtual documents, see project browser structure:
  • Package_1
    • UC diagram
  • (...)
  • Package_5
    • sub package_5.1
      • sub sub package_x.y.z
        • UC1
          • AD (Composite of UseCase)
            • Activity
              • Action1
              • (...)   
              • Final
              • Initial
        • UC2

Relations
  • UC diagram - UC: UC imported as “Link” in diagram
  • UC - AD: AD is composite child diagram of UC, stored in same package as UC
  • AD - AD elements: AD elements have the activity as parent and are stored in same package

There's need to get UC diagram, UCs, AD, activity, action, (…), initial and final included in that documentation.

The first approach to get that done was to use template and fragments. The resulting documentation contains UC diagram, UCs, but neither AD, activity nor anything being a child-child of the UseCase.

So I turned to virtual documents. In order to grab the missing AD and its diagram elements and get them reported, I tried to create a model search applied as tagged values of a model document.

But it turned out that my created model search doesn't work. I think, my approach of implementing a model search into a model document isn't correct.
Beside any general solution to my context I think I need to understand first:
How to use model search in model document?
Where do I have to write what? The modal search as a query is a custom sql of a fragment within the template that is chosen for the modal document?

I was unable to use the help in http://sparxsystems.com/forums/smf/index.php?topic=6152.0 to get a working virtual document that uses a modal search. The semi-automated approach published there by Geert is not “copyable” for me because I need to start on a package, not a diagram.

Thanks,
Shegit


PS: If you prefer to revitalize the old thread as it seems to be the topic: short notice and I will to so.
49
Automation Interface, Add-Ins and Tools / Re: Can we hijack «trace»?
« Last post by qwerty on February 16, 2018, 05:38:47 pm »
I guess that should be possible (will eventually try later). But then you have the problem that the standard toolbox still offers trace prominently and people will mix to 50% or so. Is it worth that?

q.
50
General Board / Re: Instance of a constraint block in a block's constraint compartment SysML
« Last post by KP on February 16, 2018, 04:39:07 pm »
Ctrl+drag Block X (from Project Browser) onto Block Y (on the diagram) and EA will create a part of type X. If Block X is a constraint block then the part will be a constraint property. (Note that the constraint property can either be shown as a part or in a compartment, not both, so to show the compartment you will need to remove the part from the diagram.)
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