Messages

1

General Board / Re: Mapping from logical model to fisical model

« on: March 18, 2009, 09:29:44 pm »

Can you please tell me how to execute the stored procedure defined in the same EA db

2

Automation Interface, Add-Ins and Tools / how to get tree position defined in project?

« on: March 19, 2009, 09:10:22 pm »

Hi,
I m developing adding for exporting element into xml file.

When i export the properties of class, collection order always return me different order.

So came accross another property TPos, which gives tree position.

But when i look into database. this tpos null valu as well and which i felt that tpos does not have correct value.

Or m i missing something.

I need the exact tree position defined in Project Browser for elements , packages, properties of elements , operation parameters position.

3

Automation Interface, Add-Ins and Tools / what is column t_datatype for "Set As Default"?

« on: April 16, 2009, 10:34:53 pm »

Hi,

I am creating addin similar to Database Datatypes screen,[ select the Settings | Database Datatypes menu option]
To create the new database datatypes.

I need following information

1.      How to make datatype default , as it happen the EA Datatypes Screen, by checking CheckBox “Set As Default”, what is the corresponding database column in t_datatypes

2.      What is the use of HasLength column?

3.      Can we use PDATA3 column for special use in case of user created datatypes.

4

Automation Interface, Add-Ins and Tools / Re: How to decode the encrypted connection string

« on: March 19, 2009, 08:55:46 pm »

Thank you for the reply.

5

Automation Interface, Add-Ins and Tools / How to decode the encrypted connection string

« on: March 18, 2009, 07:56:25 pm »

Hi,

Through EA api, is there any way to decode the encrypted connection string?

Repository.ConnectionString retruns the local EAP file path, and this file contains the encrpted connection string.
I want to use this connection string.

please elt me know how to get the connection string.

6

Automation Interface, Add-Ins and Tools / Re: Registry entry for all the users

« on: December 11, 2008, 09:44:20 pm »

I understand

But when i looked at addin provided by sparx "MDG Link for DOORS"

it creates registry entry "DOORS" with value "DoorsInterface.EADoors"
for all the users.

and it is created by installation package "MGD Links for DOORS" as i have noticed it in "Add/ Remove Programs"

I would like to know how it has been implemented  

7

Automation Interface, Add-Ins and Tools / Re: Registry entry for all the users

« on: December 11, 2008, 09:12:45 pm »

Hi Frank and Midnight,

Thank you for inputs,

But yes Frank is right, Addin is availble for the user whoes registry entry is avilable.

Now i have to create and Installation Package which will create the registry entry under HKEY_CURRENT_USER\Software\Sparx Systems\EAAddins.

and the user have to run this installation package.

only problem is that when installation package is installed by USER1,
USER2 wont be able to run it as it is already been installed.  

Please guide me if anyone who has installed the Addin for all the users (default users) who loggs-in to the machine.

8

Automation Interface, Add-Ins and Tools / Registry entry for all the users

« on: December 10, 2008, 10:57:25 pm »

Hi,

After following the basic steps, given in below link
http://www.sparxsystems.com/uml_tool_guide/sdk_for_enterprise_architect/deployingaddins.html

I have create the Add-in, deployed on remote machin. It works fine only for my user.

As i have created the registry entry at
HKEY_CURRENT_USER\Software\Sparx Systems\EAAddins\EATestAddin

But this addin is not available to other user who logged-in on remote machine.

What registry entry is required to be created so that addin will be avilable to all the user?

I have tried placing entry at HKEY_LOCAL_MACHINE, but did not work

Please reply.

9

Automation Interface, Add-Ins and Tools / how to check Class is conected to pk1 in hierarchy

« on: November 24, 2008, 10:11:19 pm »

how to check Class1 is is connected to pkg1 thr  many sub=pacakges.

Pkg1 -> pkg2 -> pkg3 -> pkg5 > class1

Now i have the name of class i.e. class1 and the id of main package pkg1, now i have to find that these are connected to each other.

How to do that

when i fire query

select ea_guid from t_object where name ="class1"

i get many records as name is not unques thr out the repository but only packages under pkg1

so i need to find the id which is under pkg1 only and discard other.

Please provide me the signle query to find this without affecting the performace.

Please assist.

Regards