Diagram layout

[Monsieur]

Hello sparxian,

Little nothing today, but couldn't find a solution:
[size=16]Can we manage diagram automaticaly in EA as you can do manually by defining the layout of a Driagram to Box or Digraph?[/size]

something like (THIS DOES NOT EXIST, i just dream about it)

currentDiagram.Layout(Digraph)            Repository.ReloadDiagram(currentDiagram.DiagramID)

would have been perfect :p

I saw about EA Matic, but it only manage lines no?
http://bellekens.com/2015/03/14/configure-your-own-default-line-styles-in-enterprise-architect-with-ea-matic/

I am sure there is a function but i can't find it.
Thank you

[philchudley]

Interesting

The closest I could find is the following

LayoutDiagramEx (
string DiagramGUID,
long LayoutStyle,
long Iterations,
long LayerSpacing,
long ColumnSpacing,
boolean SaveToDiagram
)

this method is defined in the Project class

This may partially address what you are looking for

Phil

[philchudley]

Follow up post, the method LayoutDiagramEx appears to use the Digraph style

Phil

[Geert Bellekens]

In one of the other examples: Self-maintaining diagrams in Enterprise Architect with EA-Matic I use automatic layout of diagram using this code below:

Code: [Select]

'layout the auto diagram
function layoutAutoDiagram(diagramID, model)
    dim diagram
    set diagram = model.getDiagramByID(DiagramID)
    'if the diagram is an auto diagram then we do an automatic layout
    if Left(diagram.name,LEN("AUTO_")) = "AUTO_" then
        'auto layout diagram
        dim diagramGUIDXml
        'The project interface needs GUID's in XML format, so we need to convert first.
        diagramGUIDXml = Repository.GetProjectInterface().GUIDtoXML(diagram.wrappedDiagram.DiagramGUID)
        'Then call the layout operation
        Repository.GetProjectInterface().LayoutDiagramEx diagramGUIDXml, lsDiagramDefault, 4, 20 , 20, false
    end if
end function
Geert

[Monsieur]

Well, thank you both!

I must look deeper into that LayoutDiagramEx function (which seem to be the only solution (but it seem a bit harsh to apprehend).

@Geert Bellekens
I 'll give a try to your function Geert (by including it into a Library and calling it). I'll give you some feedback about it. Thanks for giving pieces of your code so kindly.

Sparxians are the best  

[Geert Bellekens]

Sparxians are the best  

To avoid confusion, we usually use the term "Sparxians" to denote employees of Sparx Systems.

Neither Phil nor myself are employed by Sparx Systems, although we both work for a Sparx Systems partner.

You can recognize actual Sparxians by the red color of their name (Simon, RoyC, KP,...)

Geert

[Monsieur]

Hum sorry for my vocabulary mistake, thanks for pointing that out!

[size=18]Sparx community*[/size] is the [size=18]BEST[/size][/b]

         

[Monsieur]

So many functions i dont know!!!!

Some feedback.

Code: [Select]

'layout the auto diagram
function layoutAutoDiagram(diagramID, model) //[color=#0000ff]model is Repository ?[/color]
   dim diagram
   set diagram = model.getDiagramByID(DiagramID)
   'if the diagram is an auto diagram then we do an automatic layout
   if Left(diagram.name,LEN("AUTO_")) = "AUTO_" then
        'auto layout diagram
        dim diagramGUIDXml
        'The project interface needs GUID's in XML format, so we need to convert first.
        diagramGUIDXml = Repository.GetProjectInterface().GUIDtoXML(diagram.wrappedDiagram.DiagramGUID) [color=#0000ff]//wrappedDiagram? is that a real thing :p?[/color]
        'Then call the layout operation
        Repository.GetProjectInterface().LayoutDiagramEx diagramGUIDXml, lsDiagramDefault, 4, 20 , 20, false
   end if
end function

A normal GUID is like {B303A097-298B-4e59-8261-225E63C3AC19}, what should look like an XML guid? <GUID>B303A097-298B-4e59-8261-225E63C3AC19</GUID>??

EDIT: Okay found out.
Here is my solution (in JS):

Code: [Select]

var currentDiagram as EA.Diagram;
currentDiagram = Repository.GetCurrentDiagram();
var diagramGUIDXml
diagramGUIDXml = Repository.GetProjectInterface().GUIDtoXML(currentDiagram.DiagramGUID)
Repository.GetProjectInterface().LayoutDiagramEx(diagramGUIDXml, lsDiagramDefault, 4, 20 , 20, false);

It does not work perfectly, but it's better and i don't know how to solve the problem... It's still not as good as Layout Box or Layout Digraph.......