Code generation in c++

[sm]

Code generation in c++ does not generate the reference type for parameters of functions which are "out" parameters or "inout" parameters. What could be the reason or am I missing something here?. Let me show an example.

for eg. if F1 is a function with "out" parameter a, the code generator generates the following code.

F1 ( int a); instead of generating F1(int* a);

Any help?.

[Andreas_G]

I think the topic C++ references (and code gen) referes to a similar problem.

But it's not realy good news for you.