Simple procedure to change connector types?

[Lars]

Since I'm required to change the type of connector between a large set of functions and requirements I'm searching for a simple (fast) procedure to accomplish the task.

I'm familiar with the relationship matrix, and have found the built in export function. But is there a similiar way to import connectors and at the same time change the type of connector from e.g. Depencency (trace) to Realization?

[Stefan Bolleininger]

Hi,

i don't have any solution for the user interface, but you can do this with sql-queries or/and a script. But therefore but need to know exactly what you want to do - and on which element you cast it.

Regards

STefan

[Helmut Ortmann]

Hi,

if you have a clear rule to identify the connectors to change the type then it's possible and not that difficult to make a SQL Update Script.

Its like:
Update t_connector set .......  where (condition to indentify the correct connectors).

Kind regards,

Helmut

[qwerty]

You might get yourself started by looking into my book Inside EA  

q.

[Geert Bellekens]

It is going to be either the SQL solution, or write some small script to change the type of the connectors, or you could try to export the model to XMI, and do a find and replace to change the type of connector.
And then import the xmi again.

Geert

[Lars]

Thanks for your replies!

Scripting is possible! Though, this leads me on to yet another issue. I have a VB-script today, which establishes connectors between two elements (free of choice).

This script worked just fine before I updated to EA version 10. The type of connector is configured to be set to Dependency (trace), but is now instead defined as Abstraction (trace).

I use the following syntax:
set elementConnector = source.Connectors.AddNew ( "elementConnector", "trace" )

Any thoughts?

[qwerty]

You'd better use

Code: [Select]

set elementConnector = source.Connectors.AddNew ( "elementConnector", "Dependency" );
elementConnector.Stereotype = "trace";
q.

[Lars]

Thanks! Solved the problem.

Lars