Differentiate between an element selected in the browser or a diagram?

[Guillaume]

Hi,

I have a menu item to show in my C# addin when there is a selected element from the active diagram.
Repository.GetContextItemType() displays otElement object type when I have an element selected from the Browser or a Diagram.
Is there a way to know that my element is selected within the active diagram, and not the browser? (and vice versa i.e. I want to display a menu when my element is selected in the browser, not a diagram).

[Geert Bellekens]

Use the parameter MenuLocation

Geert

[Guillaume]

Thanks Geert 

This is indeed an information available via one of the parameters of EA_GetMenuItems, EA_GetMenuState and EA_MenuClick with one of the following values: Diagram, TreeView, MainMenu.

[Geert Bellekens]

Sorry about the short reply and lack of context. I didn't really have time to write a full answer at the time.

Geert

[Eve]

I'll just take this opportunity to recommend EA 15 as it contains a new API which may help.

Repository.CurrentSelection is documented as "Provides information on what is selected, and in what location without making any requests to the database."

EASelection Class

The Location property does what you're asking, and in greater detail than the MenuLocation property. Although I'd encourage where possible it's best to have the same behavior wherever the selection is. (The obvious exception being commands to select it in another place)

[Guillaume]

This new API method looks interesting so I'll test it.

Thanks Eve